參數(shù)資料
型號: SAK-XC2237M-104F40L
廠商: Infineon Technologies
文件頁數(shù): 92/107頁
文件大?。?/td> 0K
描述: IC MCU 16BIT 320KB FLASH 64LQFP
標準包裝: 1,900
系列: XC22xxM
核心處理器: C166SV2
芯體尺寸: 16/32-位
速度: 40MHz
連通性: CAN,EBI/EMI,I²C,LIN,SPI,SSC,UART/USART,USI
外圍設備: I²S,POR,PWM,WDT
輸入/輸出數(shù): 38
程序存儲器容量: 832KB(832K x 8)
程序存儲器類型: 閃存
RAM 容量: 50K x 8
電壓 - 電源 (Vcc/Vdd): 3 V ~ 5.5 V
數(shù)據(jù)轉(zhuǎn)換器: A/D 9x10b
振蕩器型: 內(nèi)部
工作溫度: -40°C ~ 125°C
封裝/外殼: 64-LQFP
包裝: 帶卷 (TR)
其它名稱: SP000720382
XC2238M, XC2237M
XC2000 Family / Base Line
Electrical Parameters
Data Sheet
85
V2.1, 2011-07
The timing in the AC Characteristics refers to TCSs. Timing must be calculated using the
minimum TCS possible under the given circumstances.
The actual minimum value for TCS depends on the jitter of the PLL. Because the PLL is
constantly adjusting its output frequency to correspond to the input frequency (from
crystal or oscillator), the accumulated jitter is limited. This means that the relative
deviation for periods of more than one TCS is lower than for a single TCS (see formulas
and Figure 20).
This is especially important for bus cycles using waitstates and for the operation of
timers, serial interfaces, etc. For all slower operations and longer periods (e.g. pulse train
generation or measurement, lower baudrates, etc.) the deviation caused by the PLL jitter
is negligible.
The value of the accumulated PLL jitter depends on the number of consecutive VCO
output cycles within the respective timeframe. The VCO output clock is divided by the
output prescaler K2 to generate the system clock signal
f
SYS. The number of VCO cycles
is K2
× T, where T is the number of consecutive f
SYS cycles (TCS).
The maximum accumulated jitter (long-term jitter) D
Tmax is defined by:
D
Tmax [ns] = ±(220 / (K2 × fSYS) + 4.3)
This maximum value is applicable, if either the number of clock cycles T > (
f
SYS / 1.2) or
the prescaler value K2 > 17.
In all other cases for a timeframe of T
× TCS the accumulated jitter D
T is determined by:
D
T [ns] = DTmax × [(1 - 0.058 × K2) × (T - 1) / (0.83 × fSYS - 1) + 0.058 × K2]
f
SYS in [MHz] in all formulas.
Example, for a period of 3 TCSs @ 33 MHz and K2 = 4:
D
max = ±(220 / (4 × 33) + 4.3) = 5.97 ns (Not applicable directly in this case!)
D
3 = 5.97 × [(1 - 0.058 × 4) × (3 - 1) / (0.83 × 33 - 1) + 0.058 × 4]
= 5.97
× [0.768 × 2 / 26.39 + 0.232]
= 1.7 ns
Example, for a period of 3 TCSs @ 33 MHz and K2 = 2:
D
max = ±(220 / (2 × 33) + 4.3) = 7.63 ns (Not applicable directly in this case!)
D
3 = 7.63 × [(1 - 0.058 × 2) × (3 - 1) / (0.83 × 33 - 1) + 0.058 × 2]
= 7.63
× [0.884 × 2 / 26.39 + 0.116]
= 1.4 ns
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