參數(shù)資料
型號： ADP1871ACPZ-0.3-R7
廠商： ANALOG DEVICES INC
元件分類： 穩(wěn)壓器
英文描述： SWITCHING CONTROLLER, PDSO10
封裝： 3 X 3 MM, ROHS COMPLIANT, LFCSP-10
文件頁數(shù)： 30/44頁
文件大?。?/td> 1958K
代理商： ADP1871ACPZ-0.3-R7
ADP1870/ADP1871
Therefore, an appropriate inductor selection is five 270 μF
polymer capacitors with a combined ESR of 3.5 mΩ.
Assuming an overshoot of 45 mV, determine if the output
capacitor that was calculated previously is adequate:
Rev. A | Page 30 of 44
ZERO
COMP
COMP
f
R
C
π
=
2
1
=
3
3
10
25
.
10
100
14
.
2
1
×
×
×
×
×
= 250 pF
(
)
(
10
)
2
2
2
6
2
2
2
)
)
mV
45
8
= 1.4 mF
Choose five 270 μF polymer capacitors.
The rms current through the output capacitor is
(
3
2
×
=
)
A
15
(
1
)
(
)
(
Δ
×
×
=
×
=
OUT
OVSHT
V
OUT
LOAD
OUT
V
V
I
L
C
Loss Calculations
Duty cycle = 1.8/12 V = 0.15
R
ON (N2)
= 5.4 mΩ
t
BODY(LOSS)
= 20 ns (body conduction time)
V
F
= 0.84 V (MOSFET forward voltage)
C
IN
= 3.3 nF (MOSFET gate input capacitance)
Q
N1,N2
= 17 nC (total MOSFET gate charge)
R
GATE
= 1.5 Ω (MOSFET gate input resistance)
[
N1(ON)
N1,N2(CL)
R
D
P
= (0.15 × 0.0054 + 0.85 × 0.0054) × (15 A)
2
= 1.215 W
t
P
A
49
.
V
2
13
V
8
10
300
μF
1
)
V
8
×
V
2
13
(
3
1
2
1
)
1
1
3
,
,
=
×
×
×
×
f
×
=
MAX
IN
OUT
SW
OUT
MAX
L
IN
RMS
V
V
V
V
I
(
)
]
2
LOAD
1
N2(ON)
I
R
D
×
×
+
×
=
The power loss dissipated through the ESR of the output
capacitor is
P
COUT
= (
I
RMS
)
2
×
ESR
= (1.5 A)
2
× 1.4 mΩ = 3.15 mW
Feedback Resistor Network Setup
It is recommended to use R
B
= 15 kΩ. Calculate R
T
as follows:
×
=
T
R
2
)
(
)
(
×
×
×
=
F
LOAD
SW
LOSS
BODY
LOSS
BODY
V
I
t
= 20 ns × 300 × 10
3
× 15 A × 0.84 × 2
= 151.2 mW
P
SW(LOSS)
=
f
SW
×
R
GATE
×
C
TOTAL
×
I
LOAD
×
V
IN
× 2
= 300 × 10
3
× 1.5 Ω × 3.3 × 10
9
× 15 A × 12 × 2
= 534.6 mW
(
(
[
10
3
10
300
(
62
.
×
×
×
×
+
= 57.12 mW
)
(
)
(
×
×
=
kΩ
30
V
6
V)
6
V
8
kΩ
15
=
)
[
V
]
)
]
))
002
.
0
×
10
3
10
300
(
0
))
002
.
62
+
.
9
3
9
3
)
×
(
+
×
×
×
×
×
=
+
+
+
×
=
BIAS
REG
lowerFET
SW
REG
BIAS
DR
upperFET
SW
DR
C
LOSS
DR
V
I
V
f
I
V
C
f
P
Compensation Network
To calculate R
COMP
, C
COMP
, and C
PAR
, the transconductance
parameter and the current-sense gain variable are required. The
transconductance parameter (G
M
) is 500 μA/V, and the current-
sense loop gain is
1
1
×
ON
CS
R
A
mW
6
55
)
002
.
5
10
3
×
10
300
(
)
V
5
V
13
(
)
(
9
3
=
+
×
×
+
×
×
×
=
BIAS
REG
total
SW
REG
IN
LDO
DISS
P
I
V
C
f
V
V
A/V
33
.
005
.
24
=
=
=
CS
G
where
A
CS
and
R
ON
are taken from setting up the current limit
(see the Programming Resistor (RES) Detect Circuit and Valley
Current-Limit Setting sections).
The crossover frequency is 1/12
th
of the switching frequency:
300 kHz/12 = 25 kHz
The zero frequency is 1/4
th
of the crossover frequency:
25 kHz/4 = 6.25 kHz
2
π
×
+
M
ZERO
CROSS
G
f
f
P
COUT
= (
I
RMS
)
2
×
ESR
= (1.5 A)
2
× 1.4 mΩ = 3.15 mW
2
LOAD
)
(
LOSS
DCR
P
I
DCR
×
=
= 0.003 × (15 A)
2
= 675 mW
P
CIN
= (
I
RMS
)
2
×
ESR
= (7.5 A)
2
× 1 mΩ = 56.25 mW
P
LOSS
= P
N1,N2
+ P
BODY(LOSS)
+ P
SW
+ P
DCR
+ P
DR
+ P
DISS(LDO)
+ P
COUT
+ P
CIN
= 1.215 W + 151.2 mW + 534.6 mW + 57.12 mW + 55.6
+ 3.15 mW + 675 mW + 56.25 mW
= 2.655 W
6
8
3
×
10
500
10
11
.
×
10
25
141
.
2
10
25
.
10
25
10
25
3
6
3
3
3
3
×
×
×
×
×
×
×
×
+
×
×
=
×
=
REF
OUT
V
CS
OUT
CROSS
CROSS
COMP
V
G
C
f
f
R
= 100 kΩ
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