參數(shù)資料
型號: AD8117
廠商: Analog Devices, Inc.
英文描述: Video Crosspoint Switch Video Crosspoint Switch
中文描述: 視頻交叉點(diǎn)開關(guān)視頻交叉點(diǎn)開關(guān)
文件頁數(shù): 21/32頁
文件大小: 488K
代理商: AD8117
Preliminary Technical Data
AD8117/AD8118
where
R
G
is 2.5 kΩ,
R
S
is the user single-ended source resistance
(such as 37.5 Ω for a back-terminated 75 Ω source), and
R
F
is
2.538 kΩ for the AD8117 and 5.075 kΩ for the AD8118.
Rev. PrA | Page 21 of 32
In the case of the AD8117, this is
In the case of the AD8118, this is
When operating with a differential input, care must be taken to
keep the common-mode, or average, of the input voltages
within the linear operating range of the AD8117/AD8118
receiver. This common-mode range can extend rail-to-rail,
provided the differential signal swing is small enough to avoid
forward biasing the ESD diodes (it is safest to keep the
common-mode plus differential signal excursions within the
supply voltages of the part).
The differential output of the AD8117/AD8118 receiver is
linear for a peak of 1.4V of output voltage difference (1.4 V
peak input difference for the AD8117, and 0.7 V peak input
difference for the AD8118). Taking the output differentially,
using the two output phases, this allows 2.8 V
PP
of linear output
signal swing. Beyond this level, the signal path will saturate and
limit the signal swing. This is not a desired operation, as the
supply current will increase and the signal path will be slow to
recover from clipping. The absolute maximum allowed
differential input signal is limited by long-term reliability of the
input stage. The limits in the Absolute Maximum Ratings
section of the datasheet should be observed in order to avoid
degrading device performance permanently.
50
50
OPn
AD8117
ONn
RCVR
IPn
INn
Figure 23. Example of Input Driven Differentially
AC-Coupling
It is possible to AC-couple the inputs of the AD8117/AD8118
receiver. This is simplified in that bias current does not need to
be supplied externally. A capacitor in series with the inputs to
the AD8117/AD8118 will create a high-pass filter with the input
impedance of the device. This capacitor will need to be sized
such that the corner frequency is low enough for frequencies of
interest.
Single-ended Input
The AD8117/AD8118 input receiver can also be driven single-
ended (unbalanced). From the standpoint of the receiver, there
is very little difference between signals applied positive and
negative in two phases to the input pair, versus a signal applied
to one input only with the other input held at a constant
potential. One small difference is that the common-mode
between the input pins will be changing if only one input is
moving, and there is a very small common-mode to differential
conversion gain in the receiver that will add an additional gain
error to the output (see the common-mode rejection ratio
specifications for the input stage). For low frequencies, this
gain error is negligible. The common-mode rejection ratio
degrades with increasing frequency.
When operating the AD8117/AD8118 receiver single-endedly,
the observed input resistance at each input pin is higher than in
the differential input case, due to a fraction of the receiver
internal output voltage appearing as a common-mode signal on
its input terminals, bootstrapping the voltage on the input
resistance. This single-ended input resistance can be calculated
by the formula
where
R
G
is 2.5 kΩ,
R
S
is the user single-ended source resistance
(such as 37.5 Ω for a back-terminated 75 Ω source), and
R
F
is
2.538 kΩ for the AD8117 and 5.075 kΩ for the AD8118.
In most cases, a single-ended input signal will be referred to
mid-supply, typically ground. In this case, the undriven
differential input could be connected to ground. For best
dynamic performance and lowest offset voltage, this unused
input should be terminated with an impedance matching the
driven input, instead of being directly shorted to ground. Due
to the differential feedback of the receiver, there is high-
frequency signal current in the undriven input and it should be
treated as a signal line in the board design.
R
IN
=
R
G
+
R
S
1 –
R
F
2 × (
R
G
+
R
S
+
R
F
)
G
dm
=
5.075 kΩ
2.5 kΩ +
R
S
G
dm
=
2.538 kΩ
2.5 kΩ +
R
S
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