參數(shù)資料
型號: 21103
英文描述: AMD-K6 Processor Family Thermal Solutions Application Note AMD-K6 Processor Power Supply Design Application Note
中文描述: 的AMD - K6處理器系列散熱解決方案應(yīng)用指南的AMD - K6處理器電源設(shè)計(jì)應(yīng)用指南
文件頁數(shù): 34/64頁
文件大?。?/td> 1056K
代理商: 21103
24
Decoupling and Layout Recommendations
AMD-K6
Processor Power Supply Design
21103G/0—February 1999
used is 1.8nH (two 0.7nH for the vias and 0.4nH for the
capacitor itself). The capacitor is a 0.1-
μ
F X7R multilayer
Ceramic MLC. The inductance of a capacitor is a function of the
case type. An 0612 case is assumed here.
The following steps show how the number of required
capacitors is calculated:
1. Decide what to allow as a ripple voltage budget. In this
example calculation the ripple-voltage budget = 30mV.
2. The measured AC transient current is 0.75A. This transient
current has a typical duration of 2.5 nsec. The amount of
capacitance required can now be determined using the
following equation:
I = C (dv/dt)
C = I (dt/dv) = 0.75A (2.5nsec/30mV) = 0.625
μ
F
This equation indicates that if the capacitors didn’t have
inductance, only six 0.1-
μ
F capacitors would be needed.
3. Determine the number of capacitors required based on the
inductance of the capacitor. Use the following formula:
V = L (di/dt) = L
(0.75A/2.5nsec) = 30mV
Solving for L, the allowed budget is 100pH
4. The inductance of the capacitor and via = 1.8nH (two 0.7nH
for the vias and 0.4nH from the capacitor itself). Because
each capacitor usually has two vias (one on each end), the
effective via inductance must be:
2
0.7nH + 0.4nH = 1.8nH
5. Solving the following equations for N:
1.8nH/N = 100pH
N = 1.8nH/100pH = 18
The number of capacitors required is 18.
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