
MC10E197
2–13
MOTOROLA
ECLinPS and ECLinPS Lite
DL140 — Rev 4
Voltage Divider Subsection
The element values for the voltage divider network are
calculated using the relationships presented in Equations 8,
9, and 10 with the constraint that this divider network must
produce a voltage that lies within the range 1.3V + VEE to 2.6V
+ VEE.
Restating Equation 9,
Kd =
Kol
K
φ
* Ko * K1 * Kl
From the root locus analysis Kol is determined to be:
Kol = 1.258 e51
V
MA
SEC3
From Equation 3:
K1 = A1 *
1
CIN
and the gain constant K1:
K1 = 8.42 e21
V
mA sec
From Equation 5:
Kl = Al *
RA
RlA
and the gain constant Kl is:
Kl = 2.48 e15V
V
Kd = 2.98 e6 sec –1
Having determined the gain constant Kd , the value of Rv, is
selected such that the constraints Rv > Ro and:
Kd
2
π
p2
=
Ro
Ro + Rv
are fulfilled. The pole position P2 is determined from the root
locus analysis to be:
P2 = – 2.73MHz
Hence, Rv is selected to be:
Rv = 2.15k
and Ro is calculated to be:
Ro = 453
Finally, using Equation 8a:
Cd =
1
Rv Kd
eqt. 8a
the capacitor value, Cd is calculated to be:
Cd = 156pF
Again, note the voltage divider section can be used to set the
gain, but the designer is cautioned to be sure the input value to
VCOIN is within the correct range.
Component Scaling
As mentioned, these design equations were developed for
a data rate of 20Mbit/sec. If the data rate is different from the
nominal design value the reactive elements must be scaled
accordingly. The following equations provided are to facilitate
scaling and were derived with the assumptions that a 1:7
coding scheme is used and that the RDCLK signal is twice the
frequency of the data clock:
CIN = 294 *30
f
eqt. 13
(pF)
30
f
Cd = 156 *
eqt. 14
(pF)
where f is the RDCLK frequency in MHz.
Example for an 10 Mbit/sec Data Rate
As an example of scaling, assume the given filter and a 1:7
code are used but the data rate is 10Mbit/sec. The dynamic
pole positions and, therefore, the bandwidth of the loop filter,
are a function of the data rate. Thus, a slower data rate will
force the dynamic poles and the bandwidth to move to a lower
frequency. From Equation 13 the value of CIN is:
CIN = 588pF
and from Equation 14 the value of Cd is:
Cd = 312pF
Thus, the element values for the filter are:
Filter Input Subsection:
CIN = 588pF
R1 = 1.0k
Integrator Subsection:
CA = 0.1
μ
F
RA = 5.11k
RlA = 5.11k