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參數(shù)資料
| 型號： | L7597 |
| 廠商： | Lineage Power |
| 英文描述： | Resistive Subscriber Line Interface Circuit (SLIC), Ring Relay, and Protector (SRP) for Short Loop and TA-909 Applications(用于短環(huán)路和TA-909的電阻性用戶線接口、振鈴繼電器和保護器) |
| 中文描述： | 電阻用戶線接口電路（SLIC），環(huán)繼電器和保護（SRP）的短環(huán)路和TA - 909應用（用于短環(huán)路和電訊- 909的電阻性用戶線接口，振鈴繼電器和保護器） |
| 文件頁數(shù)： | 29/34頁 |
| 文件大?。?/td> | 564K |
| 代理商： | L7597 |
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Advance Data Sheet
March 1997
Lucent Technologies Inc.
29
Relay, and Protector (SRP) for Short Loop and TA-909 Applications
L7597 Resistive Subscriber Line Interface Circuit (SLIC), Ring
ac Design
(continued)
Design Equations
(continued)
12-3429 (F).r3
Figure 11. Initial ac Interface for Complex Termination Between L7597 SLIC and T7504 Codec
Note: dc Blocking Capacitor (C
B
) Not Shown, C
T
and C
R
Separate
V
RN
RECEIVE
INTERFACE
+
–
R
T2
R
RV2
R
HB1
R
GX
G
SX
VFXIN
VFRO
1/4 T7504 CODEC
Z
T/R
+
–
V
T/R
I
T/R
+2.4 V
C
R
1/2 L7597
R
GX1
R
RV1
C
T
R
T1
Z
IRP
–
+
AX
V
XMT
L
RP
V
RN
XMT
I
RP
PT
PR
V
BAT
TS
RS
V
BAT
R
1
R
2
C
1
RESISTOR
MODULE
200 k
200 k
100 k
200
200
100 k
1 k
1 k
The Tip/Ring differential current is given by:
The voltage at pin XMT is given by:
The component values in the ac interface of Figure 11
are calculated (for the transmit and receive gains
defined by the respective gain constants K
RX
and K
RCV
,
and for the termination impedance seen in Figure 10)
using the following equations:
The 200
feed resistors contribute 400
to the termi-
nation impedance. The termination impedance associ-
ated with the circuit in Figure 11 consists of this
inherent 400
feeding impedance in parallel with:
I
A negative impedance, where,
100
R
GX1
I
And a positive impedance, where,
The negative and positive impedance terms are used
to adjust the termination impedance from the inherent
400
to any complex termination.
I
T/R
200 I
RP
RN
Z
IRP
V
–
=
V
XMT
T/R
2
--V
=
R
RV1
1
′
K
RCV
2
′
K
RCV
RCV
C
′
100
100R
=
R
RV2
100R
=
C
R
K
=
GX1
R
GX1
400
= 2 x 200
feed resistors
R
GX
2 *K
TX
R
GX1
=
′
100
R
T1
R
T1
+
--------R
RV1
100
R
400
--1
1
1
′
R
–
=
R
T1
1
′
R
RV1
+
(
)
C
T
--C
GX1
R
100R
+
+
=
R
T2
2
′
C
′
C
T
R
=
---2
x
GX1
R
T1
+
--------R
R
T2
ω
C
T
-------------
+
R
----------R
R
+
T1
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