參數(shù)資料
型號(hào)： TLC320AD81CDBTR
廠商： TEXAS INSTRUMENTS INC
元件分類： 音頻控制
英文描述： 2 CHANNEL(S), EQUALIZER CIRCUIT, PDSO38
封裝： PLASTIC, TSSOP-38
文件頁數(shù)： 31/47頁
文件大?。?/td> 195K
代理商： TLC320AD81CDBTR
A–1
Appendix A
Software Interface
Table A–1. Register Map
REGISTER
ADDRESS
NO. of
BYTES
BYTE DESCRIPTION
Reserved
0x00
MCR
0x01
1
C(7–0)
Reserved
0x02
Reserved
0x03
Volume
0x04
6
VL(23–16), VL(15–8), VL(7–0), VR(23–16), VR(15–8), VR(7–0)
Treble
0x05
1
T(7–0)
Bass
0x06
1
B(7–0)
Mixer 1
0x07
3
S(23–16), S(15–8), S(7–0)
Mixer 2
0x08
3
S(23–16), S(15–8), S(7–0)
Reserved
0x09
Left
Biquad 0
0x0A
15
B0(23–16), B0(15–8), B0(7–0), B1(23–16), B1(15–8), B1(7–0), B2(23–16),
B2(15–8), B2(7–0), A1(23–16), A1(15–8), A1(7–0), A2(23–16), A2(15–8),
A2(7–0)
Left
Biquad 1
0x0B
15
B0(23–16), B0(15–8), B0(7–0), B1(23–16), B1(15–8), B1(7–0), B2(23–16),
B2(15–8), B2(7–0), A1(23–16), A1(15–8), A1(7–0), A2(23–16), A2(15–8),
A2(7–0)
Left
Biquad 2
0x0C
15
B0(23–16), B0(15–8), B0(7–0), B1(23–16), B1(15–8), B1(7–0), B2(23–16),
B2(15–8), B2(7–0), A1(23–16), A1(15–8), A1(7–0), A2(23–16), A2(15–8),
A2(7–0)
Left
Biquad 3
0x0D
15
B0(23–16), B0(15–8), B0(7–0), B1(23–16), B1(15–8), B1(7–0), B2(23–16),
B2(15–8), B2(7–0), A1(23–16), A1(15–8), A1(7–0), A2(23–16), A2(15–8),
A2(7–0)
Left
Biquad 4
0x0E
15
B0(23–16), B0(15–8), B0(7–0), B1(23–16), B1(15–8), B1(7–0), B2(23–16),
B2(15–8), B2(7–0), A1(23–16), A1(15–8), A1(7–0), A2(23–16), A2(15–8),
A2(7–0)
Left
Biquad 5
0x0F
15
B0(23–16), B0(15–8), B0(7–0), B1(23–16), B1(15–8), B1(7–0), B2(23–16),
B2(15–8), B2(7–0), A1(23–16), A1(15–8), A1(7–0) A2(23–16), A2(15–8),
A2(7–0)
Reserved
0x10
Reserved
0x11
Reserved
0x12
The volume value is a 4.16 coefficient. In order to transmit it over I2C, it is necessary to separate the value into three
bytes. Byte 2 is the integer part and bytes 1 and 0 are the fractional parts.
The mixer gain values and biquad coefficients are 4.20 coefficients. In order to transmit them over I2C, it is necessary
to separate the value into three bytes. The first nibble of byte 2 is the integer part and the second nibble of byte 2 and
bytes 1 and 0 being the fractional parts.
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