參數(shù)資料
型號: TDA8944AJ
廠商: NXP SEMICONDUCTORS
元件分類: 音頻/視頻放大
英文描述: 7 W, 2 CHANNEL, AUDIO AMPLIFIER, PZIP17
封裝: PLASTIC, DIL-BENT-SIL, 17 PIN
文件頁數(shù): 16/20頁
文件大?。?/td> 376K
代理商: TDA8944AJ
Philips Semiconductors
TDA8944AJ
2 x 7 W BTL audio amplier with DC gain control
Product data
Rev. 01 — 01 March 2002
5 of 20
9397 750 09433
Koninklijke Philips Electronics N.V. 2002. All rights reserved.
The input cut-off frequency is:
(1)
For Ri = 32 k and Ci = 220 nF:
(2)
As shown in Equation 2, large capacitors values for the inputs are not necessary; so
the switch-on delay during charging of the input capacitors can be minimized. This
results in a good low frequency response and good switch-on behaviour.
Remark: To prevent high frequency oscillations do not leave the inputs open, connect
a capacitor of 4.7 nF across the input pins close to the device (see Figure 15).
8.2 Power amplier
The power amplier is a Bridge-Tied Load (BTL) amplier with an all-NPN output
stage, capable of delivering a peak output current of 2 A.
The BTL principle offers the following advantages:
Lower peak value of the supply current
The ripple frequency on the supply voltage is twice the signal frequency
No expensive DC-blocking capacitor
Good low frequency performance.
8.2.1
Output power measurement
The output power as a function of the supply voltage is measured on the output pins
at THD = 10%; see Figure 10. The maximum output power is limited by the supply
voltage of 12 V and the maximum available output current: 2 A repetitive peak
current.
8.2.2
Headroom
Typical CD music requires at least 12 dB (factor 15.85) dynamic headroom -
compared to the average power output - for transferring the loudest parts without
distortion. At VCC =12V, RL =8 and Po = 4 W at THD = 0.2% (see Figure 8), the
Average Listening Level (ALL) - music power - without any distortion yields:
(3)
The power dissipation can be derived from Figure 12 on page 11 for 0 dB
respectively 12 dB headroom.
f
i cut
off
()
1
2
π 0.5 R
i
C
i
×
()
------------------------------------------
=
f
i cut
off
()
1
2
π 0.5 32
×
10
3
220
10
9
×
()
------------------------------------------------------------------------------
45.2 Hz
==
P
oALL
()
4 W
15.85
-------------
252.4
=mW
=
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