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| 型號： | MP1567DQ |
| 廠商： | MONOLITHIC POWER SYSTEMS INC |
| 元件分類： | 穩(wěn)壓器 |
| 英文描述： | 1.2A Synchronous Rectified Step-Down Converter |
| 中文描述： | 2 A SWITCHING REGULATOR, 800 kHz SWITCHING FREQ-MAX, PDSO10 |
| 封裝： | 3 X 3 MM, MO-229VEED-5, QFN-10 |
| 文件頁數(shù)： | 8/11頁 |
| 文件大小： | 309K |
| 代理商： | MP1567DQ |
MP1567 – 1.2A SYNCHRONOUS RECTIFIED STEP-DOWN CONVERTER
MP1567 Rev. 2.3
1/3/2006
www.MonolithicPower.com
8
MPS Proprietary Information. Unauthorized Photocopy and Duplication Prohibited.
2006 MPS. All Rights Reserved.
TM
75KHz or lower to insure stable operation.
Lower crossover frequencies result in slower
response and worse transient load recovery.
Higher crossover frequencies degrade the
phase and/or gain margins and can result in
instability.
Choosing the Compensation Components
The values of the compensation components
given in Table 1 yield a stable control loop for
the output voltage and capacitor given.
Table 1—Compensation Values for Typical
Output Voltage/Capacitor Combinations
V
OUT
C2
R3
C3
C4
1.8V
2.5V
3.3V
1.8V
2.5V
3.3V
4.7
μ
F Ceramic
4.7
μ
F Ceramic
4.7
μ
F Ceramic
10
μ
F Ceramic
10
μ
F Ceramic
10
μ
F Ceramic
47
μ
F Tantalum
(300m
)
47
μ
F Tantalum
(300m
)
47
μ
F Tantalum
(300m
)
3.3k
5.1k
6.8k
7.5k
10k
10k
2.2nF
1.5nF
1.2nF
1nF
820pF None
820pF None
None
None
None
None
1.8V
10k
2.2nF 1.5nF
2.5V
10k
3.3nF 1.5nF
3.3V
10k
4.7nF 1.5nF
To optimize the compensation components for
conditions not listed in Table 1, use the
following procedure.
Choose the compensation resistor to set the
desired crossover frequency. Determine the
value by the following equation:
FB
CS
EA
C
OUT
V
V
G
G
f
2
×
C
2
3
R
×
×
×
×
π
=
Putting in the known constants and setting the
crossover frequency to the desired 75KHz:
OUT
V
8
2
C
10
36
.
3
R
×
×
×
≈
In this case, the actual crossover frequency is
less than the desired 75KHz, and it is
calculated by:
OUT
V
FB
CS
EA
×
C
2
C
2
V
G
×
G
π
3
R
f
×
×
×
=
Choose the compensation capacitor to set the
zero to one fourth of the crossover frequency.
Determine the value by the following equation:
FB
CS
EA
2
OUT
V
V
G
G
3
R
2
C
4
×
3
C
×
×
×
×
=
Determine
capacitor, C4, is required. It is required if the
ESR zero of the output capacitor occurs at less
than four times the crossover frequency, or:
if
the
second
compensation
1
f
R
2
C
8
C
ESR
≥
×
×
×
π
Where R
ESR
is the equivalent series resistance
of the output capacitor.
If this is the case, then add the second
compensation capacitor. Determine the value
by the equation:
3
R
R
2
C
4
C
)
MAX
(
ESR
×
=
Where R
ESR(MAX)
is the maximum ESR of the
output capacitor.
For Example:
Given:
V
OUT
= 1.8V
C2 = 10
μ
F Ceramic (ESR = 10m
max.)
Calculate:
=
×
μ
×
≈
k
85
.
)
V
8
)
F
10
(
10
36
.
3
R
8
(Use the nearest standard value of 7.5k
.)
nF
05
.
V
8
×
F
10
10
9
3
C
14
=
μ
×
=
(Use 1nF since it is a standard value.)
2
C
8
×
×
π
19
.
f
R
C
ESR
=
×
which is less than 1, therefore the second
compensation capacitor (C4) is not required.
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