參數(shù)資料
型號(hào): LTC3406ES5-1.2#PBF
廠商: LINEAR TECHNOLOGY CORP
元件分類: 穩(wěn)壓器
英文描述: 1.3 A SWITCHING REGULATOR, 1800 kHz SWITCHING FREQ-MAX, PDSO5
封裝: PLASTIC, SOT-23, 5 PIN
文件頁數(shù): 12/12頁
文件大小: 228K
代理商: LTC3406ES5-1.2#PBF
9
LTC3406-1.2
340612fa
APPLICATIO S I FOR ATIO
WU
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1. The VIN quiescent current is due to two components:
the DC bias current as given in the electrical character-
istics and the internal main switch and synchronous
switch gate charge currents. The gate charge current
results from switching the gate capacitance of the
internal power MOSFET switches. Each time the gate is
switched from high to low to high again, a packet of
charge, dQ, moves from VIN to ground. The resulting
dQ/dt is the current out of VINthat is typically larger than
the DC bias current. In continuous mode, IGATECHG =
f(QT + QB) where QT and QB are the gate charges of the
internal top and bottom switches. Both the DC bias and
gate charge losses are proportional to VIN and thus
their effects will be more pronounced at higher supply
voltages.
2. I2R losses are calculated from the resistances of the
internal switches, RSW, and external inductor RL. In
continuous mode, the average output current flowing
through inductor L is “chopped” between the main
switch and the synchronous switch. Thus, the series
resistance looking into the SW pin is a function of both
top and bottom MOSFET RDS(ON) and the duty cycle
(DC) as follows:
RSW = (RDS(ON)TOP)(DC) + (RDS(ON)BOT)(1 – DC) (2)
The RDS(ON) for both the top and bottom MOSFETs can
be obtained from the Typical Performance Charateristics
curves. Thus, to obtain I2R losses, simply add RSW to
RL and multiply the result by the square of the average
output current.
Other losses including CIN and COUT ESR dissipative
losses and inductor core losses generally account for less
than 2% total additional loss.
Thermal Considerations
In most applications the LTC3406-1.2 does not dissipate
much heat due to its high efficiency. But, in applications
where the LTC3406-1.2 is running at high ambient tem-
perature with low supply voltage, the heat dissipated may
exceed the maximum junction temperature of the part. If
the junction temperature reaches approximately 150
°C,
both power switches will be turned off and the SW node
will become high impedance.
To avoid the LTC3406-1.2 from exceeding the maximum
junction temperature, the user will need to do some
thermal analysis. The goal of the thermal analysis is to
determine whether the power dissipated exceeds the
maximum junction temperature of the part. The tempera-
ture rise is given by:
TR = (PD)(θJA)
where PD is the power dissipated by the regulator and θJA
is the thermal resistance from the junction of the die to the
ambient temperature.
The junction temperature, TJ, is given by:
TJ = TA + TR
where TA is the ambient temperature.
As an example, consider the LTC3406-1.2 with an input
voltage of 2.7V, a load current of 600mA and an ambient
temperature of 70
°C. From the typical performance graph
of switch resistance, the RDS(ON) at 70°C is approximately
0.52
for the P-channel switch and 0.42 for the
N-channel switch. Using equation (2) to find the series
resistance looking into the SW pin gives:
RSW = 0.52(0.44) + 0.42(0.56) = 0.46
Therefore, power dissipated by the part is:
PD = ILOAD2 RSW = 165.6mW
For the SOT-23 package, the
θJA is 250°C/W. Thus, the
junction temperature of the regulator is:
TJ = 70°C + (0.1656)(250) = 111.4°C
which is below the maximum junction temperature of
125
°C.
Note that at higher supply voltages, the junction tempera-
ture is lower due to reduced switch resistance (RSW).
Checking Transient Response
The regulator loop response can be checked by looking at
the load transient response. Switching regulators take
several cycles to respond to a step in load current. When
a load step occurs, VOUT immediately shifts by an amount
equal to (
ILOAD ESR), where ESR is the effective series
resistance of COUT. ILOAD also begins to charge or
discharge COUT, which generates a feedback error signal.
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