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參數(shù)資料
| 型號： | L6238SQT |
| 廠商： | 意法半導(dǎo)體 |
| 英文描述： | 12V SENSORLESS SPINDLE MOTOR CONTROLLER |
| 中文描述： | 12V的無傳感器主軸電機控制器 |
| 文件頁數(shù)： | 24/31頁 |
| 文件大?。?/td> | 324K |
| 代理商： | L6238SQT |
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The relation between thesevariables is given by:
V
=
L
mtr
di
mtr
dt
R
mtr
i
mtr
+
E
g
(5.1.2)
where:
V
=
AppliedVoltage
i
mtr
=
MotorCurrent
L
mtr
=
Total
windings
inductance
of
the
motor
R
mtr
=
Resistancein series with the motor
E
g
=
The internally generated voltage of
the motor, proportional to the motor
velocity
Since:
E
g
The above equations can be combined to form
the basic electrical equation fora motor:
= K
E
ω
(5.1.3)
V
=
L
mtr
di
mtr
dt
R
mtr
i
mtr
+
K
E
ω
(5.1.4)
Figure 5.5 is a simplified electrical equivalent of
the output stage of the L6238S along with the
model of the motor during the time that the Out-
putDrives areconducting.
The additionalresistance associated with the out-
put stage and sensing resistor are also in series
with the motor. If we let R
s
equal the total series
resistence:
R
s
= 2*R
dsON
+ R
mtr
+ R
sense
(5.1.5)
then (5.1.4)becomes:
V
=
L
mtr
di
mtr
dt
R
s
i
mtr
+
E
g
(5.1.6)
Figure 5-6 is an equivalent circuit of the output
stage during the Constant-OFFperiod. During the
OFF time the lower driver for the particular phase
beign driven remains ON.
The internally generated voltage forces the path
of current though the motor, its series resistance,
the RdsONof the Lower Driver and finally through
the oppositelower driver.
PWM Example (Referto Figure 5-7)
The following is an example on how to select the
timing parameters.
Given:
DCStart Current
=
1.25A
Ripple Current
=
100mA
Duty Cycle
=
50%
Motor Interface(L)
=
880
μ
H
4.8
Total Series Resistance(R
s
)
If the worst case start current is 1.25A and the
duty cycle is 50%, then the Peak Current, It will
be:
i
t
=
1.25
+
0.1
2
i
t
= 1.30A
=
Eg
+
-
Rmtr
Lmtr
D95IN321
Figure 5-4
+
-
LOWER
Rdson
Rmtr
Lmtr
D95IN322
UPPER
Rdson
KEW
Rsense
Figure 5-5
+
-
Rmtr
Lmtr
D95IN323
KEW
LOWER
Rdson
LOWER
Rdson
Figure5-6
L6238S
24/31
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