參數(shù)資料
型號(hào): L3235T
英文描述: Subscriber Line Interface Circuit
中文描述: 用戶線接口電路
文件頁(yè)數(shù): 16/26頁(yè)
文件大小: 457K
代理商: L3235T
Two wire impedance
To calculate the impedance presented to the two
wire line by the SLIC including the protection re-
sistorsR
p
and definedas Z
S
let:
V
rx
= 0
Il/50’ = Il/50 (in first approximation)
Rp = 50
Z
S
= Z
AC
/25 + 2R
P
Z
AC
to make Z
S
= 600
Z
AC
= 25
(Z
S
- 2R
P
)
Z
AC
= 25
(600 - 100)
Z
AC
= 12.5K
Two wire to four wire gain
(Txgain)
Let V
rx
= 0
G
tx
=V
tx
V
l
V
tx
V
l
Z
AC
+
50R
P
Example: Calculate Gtx making R
PC
= 50
R
P
G
tx
=
2
Z
AC
+
50
R
P
Z
AC
+
50
R
P
=
2
As you can see the RPC resistor is providing the
compensation of the insertion loss introduced by
the two external protectionresistors R
P
.
= 2
Z
AC
+
R
PC
Four wire to two wire gain
(Rx gain)
Let Eg = 0
G
rx
=V
l
V
rx
25
(
Z
l
+
2R
P
)
+
Z
AC
Example:
Calculate G
rx
making Z
AC
= 25
(Z
ML
- 2
R
P
)
50
Z
l
25
(
Z
l
+
2R
P
2R
P
+
Z
ML
)
=
50
Z
l
G
rx
=
G
rx
=
2
Z
l
Z
l
+
Z
ML
In particular for Z
S
= Z
l
: G
rx
= 1
Hybrid function
To calculatedthe transhybridloss (Thl) let: Eg = 0
Thl =
=
VT
x
50
(
2
R
P
+
Z
l
)
2R
AC
)
Example:
Calculating Thl making R
S
= 50
R
P
, Z
S
= 25
(ZSlic - 2
R
P
)
Z
B
Z
B
+
Z
A
In particularifZ
A
Z
B
Z
l
Thl = 0
From the above relation it is evident that if Z
S
is
equal to the Z
l
used in Thl test, the two Z
A
, Z
B
im-
pedancescan be two resistor of the same value.
VR
x
=
4
(
Z
B
Z
B
+
Z
A
50
(
2
R
P
+
Z
l
)
2R
PC
Thl = 4
(
Z
l
Z
l
+
Z
ML
)
=
Z
S
ACtransmissioncircuit stability
To ensure stability of the feedback loop shown in
block diagram form in figure 15 two capacitorsare
required. Figure 16 includes these capacitors Cc
and Ch.
AC - DCseparation
The high pass filter capacitor C
AC
provides the
separationbetween DC circuitsand AC circuits. A
CAC value of 100mF will position the low end fre-
quencyresponse 3dBbreak pointat 7Hz,
fsp =
1
2
π
220
C
AC
Figure15:
Simplified AC Circuits
L3234 - L3235
16/26
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