參數(shù)資料
型號(hào): FAN8035L
英文描述: MOTOR CONTROLLER
中文描述: 電機(jī)控制器
文件頁數(shù): 37/191頁
文件大?。?/td> 2018K
代理商: FAN8035L
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FAN1582
PRODUCT SPECIFICATION
6
P
A protection diode between the input and output pins is usu-
ally not needed. An internal diode between the input and the
output pins on the FAN1582 series can handle microsecond
surge currents of 50A to 100A. Even with large value output
capacitors it is difficult to obtain those values of surge cur-
rents in normal operation. Only with large values of output
capacitance, such as 1000μF to 5000μF, and with the input
pin instantaneously shorted to ground can damage occur. A
crowbar circuit at the input can generate those levels of current;
a diode from output to input is then recommended, as shown
in Figure 1. Usually, normal power supply cycling or system
“hot plugging and unplugging” will not generate current
large enough to do any damage.
The adjust pin can be driven on a transient basis ±7V with
respect to the output, without any device degradation. As with
any IC regulator, exceeding the maximum input-to-output
voltage differential causes the internal transistors to break
down and none of the protection circuitry is then functional.
Figure 1. Optional Protection Diode
Ripple Rejection
In applications that require improved ripple rejection, a bypass
capacitor from the adjust pin of the FAN1582 to ground
reduces the output ripple by the ratio of V
OUT
/1.25V. The
impedance of the adjust pin capacitor at the ripple frequency
should be less than the value of R1 (typically in the range of
100
to 120
) in the feedback divider network in Figure 1.
Therefore, the value of the required adjust pin capacitor is a
function of the input ripple frequency. For example, if R1 equals
100
and the ripple frequency equals 120Hz, the adjust pin
capacitor should be 22μF. At 10kHz, only 0.22μF is needed.
Output Voltage
The FAN1582 regulator develops a 1.25V reference voltage
between the output pin and the adjust pin (see Figure 2).
Placing a resistor R1 between these two terminals causes a
constant current to flow through R1 and down through R2 to
set the overall output voltage. Normally, this current is the
specified minimum load current of 10mA.
The current out of the adjust pin adds to the current from R1
and is typically 35μA. Its output voltage contribution is small
and only needs consideration when a very precise output
voltage setting is required.
Figure 2. Basic Regulator Circuit
Load Regulation
The FAN1582 family provides true remote sensing, eliminat-
ing output voltage errors due to trace resistance. To utilize
remote sensing, connect the VSENSE pin directly to the
load, rather than at the VOUT pin. If the load is more than 1"
away from the FAN1582, it may be necessary to increase the
load capacitance to ensure stability.
Thermal Considerations
The FAN1582 series protect themselves under overload con-
ditions with internal power and thermal limiting circuitry.
However, for normal continuous load conditions, do not exceed
maximum junction temperature ratings. It is important to
consider all sources of thermal resistance from junction-to-
ambient. These sources include the junction-to-case resistance,
the case-to-heat sink interface resistance, and the heat sink
resistance. Thermal resistance specifications have been
developed to more accurately reflect device temperature and
ensure safe operating temperatures. The electrical character-
istics section provides a separate thermal resistance and
maximum junction temperature for both the control circuitry
and the power transistor. Calculate the maximum junction
temperature for both sections to ensure that both thermal
limits are met.
For example, look at using an FAN1582T-1.5 to generate 3A
@ 1.5V ± 2% from a 3.3V source (3.2V to 3.6V).
FAN1582
Adj
Vin
C2
22
μ
F
V
OUT
+
C1
10
μ
F
+
C
ADJ
+
Vcntl
Vsense
Vout
R1
R2
D1
1N4002
(OPTIONAL)
V
IN
V
OUT
FAN1582–1.5, 2.5
Gnd
Vin
C2
22
μ
F
V
OUT
+
C1
10
μ
F
+
Vcntl
Vsense
Vout
D1
1N4002
(OPTIONAL)
V
IN
V
CNTL
C2
22
μ
F
V
IN
V
OUT
V
REF
C1
10
μ
F
V
cntl
+
+
Vcntl
Vsense
Vin
Adj
Vout
FAN1582
R1
R2
I
ADJ
50
μ
A
V
OUT
= V
REF
(1+R2/R1) + I
ADJ
(R2)
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