參數(shù)資料
型號(hào): TZA1047HL/M3
廠商: NXP SEMICONDUCTORS
元件分類: 消費(fèi)家電
英文描述: SPECIALTY CONSUMER CIRCUIT, PQFP64
封裝: 10 X 10 MM, 1.4 MM HEIGHT, PLASTIC, MS-026, SOT314-2, LQFP-64
文件頁(yè)數(shù): 19/69頁(yè)
文件大?。?/td> 324K
代理商: TZA1047HL/M3
9397 750 14664
Koninklijke Philips Electronics N.V. 2005. All rights reserved.
Product data sheet
Rev. 02 — 1 June 2005
26 of 69
Philips Semiconductors
TZA1047
Preprocessor IC for CD and DVD rewritable
7.10.2.2
TH1 and TH2
TH1 and TH2 are the sampling signals used in the Input circuit. When bit EFMON equals
bit SMPLON = 1 they are generated according to the timing diagram in Figure 13.
The auxiliary signal LIGHT represents the laser light. It has a delay (17 + D2) × T with
respect to signal efmd, where D2 is a programmable parameter that is used to
synchronize signals within TZA1047 with the actual laser light pulse. If bit P/L = 1, TH1
starts in a pit region, if bit P/L = 0, TH1 starts in a land region. The leading edge of TH1
occurs ‘m’ periods of T/2 either after the start (bit L/T = 1) or before the end (bit L/T = 0) of
a pit (bit P/L = 1) or a land (bit P/L = 0). The width of TH1 equals ‘n’ periods of T/2. The
signal TH2 has its rising edge at the falling edge of TH1, and its falling edge 2T later, for all
EFM run lengths.
In the timing diagram, two versions of TH1 and TH2 are shown, for the rst version,
bit P/L = 1, bit L/T = 1, m = 1, n = 3; for the second version, bit P/L = 0, L/T = 0, m = 3,
n = 2. If bit SMPLON = 0, EFMON = 0 or r/w = 1, signals TH1 and TH2 are always HIGH.
It is possible to disable sampling for a specic run length ofN<NDIS1, where N is the run
length and NDIS1 is the run length discrimination parameter. TH1 and TH2 will remain
LOW when N < NDIS1, bit EFMON = bit SMPLON = 1, r/w = 0, and the sample-and-hold
remains in hold. This feature is called run length discrimination and is added, if needed,
to avoid critical timing at very high speeds.
Fig 13. Sampling signals TH1 and TH2.
mce521
T/2
T
EFMc
EFMd
LIGHT
TH1
(P/L = 1)
TH2
(P/L = 1)
TH1
(P/L = 0)
TH2
(P/L = 0)
pit
land
(17
+ D2) × T
n
× T/2
2T
n
× T/2
N
× T
m
× T/2
(L/T = 1)
m
× T/2
(L/T = 1)
m
× T/2
(L/T = 0)
m
× T/2
(L/T = 0)
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