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參數(shù)資料
| 型號(hào)： | PCF8831U |
| 廠商： | NXP SEMICONDUCTORS |
| 元件分類： | 顯示驅(qū)動(dòng)器 |
| 英文描述： | STN RGB - 160 output row driver |
| 中文描述： | LIQUID CRYSTAL DISPLAY DRIVER, UUC272 |
| 封裝： | DIE-272 |
| 文件頁數(shù)： | 11/28頁 |
| 文件大?。?/td> | 109K |
| 代理商： | PCF8831U |
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2002 Aug 14
11
Philips Semiconductors
Preliminary specification
STN RGB - 160 output row driver
PCF8831
10 DC CHARACTERISTICS
(V
DD
V
SS
) = 2.4 to 3.5 V; (V
H
V
L
) = 15 to 55 V; T
amb
=
40 to +85
°
C; unless otherwise specified.
Notes
1.
The minimum level of (V
MH
V
M
) depends on (V
M
V
L
); a lower level of (V
M
V
L
) requires lower offset of V
MH
referred to V
M
. A higher level of (V
MH
V
M
) improves dynamic behaviour. A minimum level of
(V
MH
V
M
) = 2.5 V + 0.2
×
(V
M
V
L
) should be maintained.
Row outputs tested one at a time.
2.
3.
(V
H
V
L
) = 37 V; V
MH
= V
H
; (V
DD
V
SS
) = 2.8 V;
; (V
M
V
SS
) = 1.47 V.
4.
f
RCLK
= 19.2 kHz; SVM = 0; ROWRES1 = ROWRES2 = HIGH; single line mode; all row outputs open-circuit.
5.
Frame inversion frequency
.
SYMBOL
PARAMETER
CONDITIONS
MIN.
TYP.
MAX.
UNIT
V
L
LOW-level LCD driving
voltage
HIGH-level LCD driving
voltage
MID-level LCD driving
voltage
0
V
V
V
L
+ 15.0
V
L
+ 45.0
V
V
M
V
SS
V
DD
V
V
MH
auxiliary supply voltage for
row switching
logic supply negative
voltage
logic supply positive voltage
HIGH-level input voltage
note 1
V
M
+ 10
V
L
+ 40
V
V
SS
V
M
2.0
V
M
1.25
V
V
DD
V
IH
V
SS
+ 2.4
V
SS
+ 0.8
×
(V
DD
V
SS
)
V
SS
V
SS
+ 3.5
V
DD
V
V
all inputs; referred to V
SS
V
IL
LOW-level input voltage
all inputs; referred to V
SS
V
SS
+ 0.2
×
(V
DD
V
SS
)
V
I
LI
input leakage current
all inputs
V
I
= V
DD
V
I
= V
SS
notes 2 and 3
I
O
= +100
μ
A
I
O
=
±
100
μ
A
I
O
=
100
μ
A
notes 3, 4 and 5
5
5
μ
A
μ
A
R
O
row output on-state
resistance
600
600
600
30
10
3
2
13
tbf
tbf
tbf
tbf
tbf
tbf
tbf
tbf
μ
A
μ
A
μ
A
μ
A
μ
A
I
DD
I
VH
I
VMH
I
VM
I
VL
current at pad V
DD
current at pad V
H
current at pad V
MH
current at pad V
M
current at pad V
L
V
--------------------
V
H
+
2
V
M
V
--------------------
V
L
+
2
=
f
FI
f
2
×
160
-------------------
=
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