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參數(shù)資料
| 型號： | op297 |
| 廠商： | Analog Devices, Inc. |
| 英文描述： | Dual Low Bias Current Precision Operational Amplifier(低偏置電流精密雙運放) |
| 中文描述： | 雙低偏置電流高精度運算放大器（低偏置電流精密雙運放） |
| 文件頁數(shù)： | 10/16頁 |
| 文件大小： | 193K |
| 代理商： | OP297 |
8/21/97 4:00 PM
OP297
–10–
REV. D
NONLINEAR CIRCUITS
Due to its low input bias currents, the OP297 is an ideal log
amplifier in nonlinear circuits such as the square and square-
root circuits shown in Figures 34 and 35. Using the squaring
circuit of Figure 34 as an example, the analysis begins by writing
a voltage loop equation across transistors Q
1
, Q
2
, Q
3
and Q
4
.
V
T
1
ln
I
IN
I
S
1
+
V
T
2
ln
I
IN
I
S
2
=
V
T
3
ln
I
O
I
S
3
+
V
T
4
ln
I
REF
I
S
4
All the transistors of the MAT04 are precisely matched and at
the same temperature, so the I
S
and V
T
terms cancel, giving:
2 ln I
IN
= ln I
O
+ ln I
REF
= ln (I
O
×
I
REF
)
Exponentiating both sides of the equation leads to:
I
O
=
(
I
IN
)
2
I
REF
Op amp A
2
forms a current-to-voltage converter which gives
V
OUT
= R2
×
10. Substituting (V
IN
/R1) for I
IN
and the above
equation for I
O
yields:
V
OUT
=
R
2
I
REF
V
IN
R
1
2
A similar analysis made for the square-root circuit of Figure 35
leads to its transfer function:
V
OUT
=
R
2(
V
IN
)(
I
REF
)
R
1
Figure 34. Squaring Amplifier
V
IN
33k
1/2
OP-297
A
1
+
2
3
8
1
4
V–
V+
C
1
100pF
C
2
100pF
R
2
33k
R
1
I
O
I
IN
I
REF
V
OUT
1/2
OP-297
A
2
+
6
5
7
MAT-04E
Q
1
1
3
2
Q
4
12
14
13
Q
2
7
5
6
Q
3
8
10
9
50k
R
3
50k
R
4
–15V
–
–
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相關代理商/技術參數(shù) |
參數(shù)描述 |
|---|---|
| OP-297 | 制造商:AD 制造商全稱:Analog Devices 功能描述:DUAL LOW BIAS CURRENT PRECISION OPERATIONAL AMPLIFIER |
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| OP297_06 | 制造商:AD 制造商全稱:Analog Devices 功能描述:Dual Low Bias Current Precision Operational Amplifier |
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