• 參數(shù)資料
    型號(hào): LX1671EVALKIT
    元件分類: 基準(zhǔn)電壓源/電流源
    英文描述: RADIATION HARDENED HIGH EFFICIENCY, 5 AMP SWITCHING REGULATORS
    中文描述: 抗輻射高效,5安培開關(guān)穩(wěn)壓器
    文件頁數(shù): 15/21頁
    文件大?。?/td> 554K
    代理商: LX1671EVALKIT
    Microsemi
    Integrated Products, Power Management
    11861 Western Avenue, Garden Grove, CA. 92841, 714-898-8121, Fax: 714-893-2570
    Page 15
    Copyright
    2000
    Rev. 0.5i, 2002-07-17
    W
    M
    .
    C
    LX1671
    Multiple Output LoadSHARE PWM
    P
    RELIMINARY
    I N T E G R A T E D P R O D U C T S
    THEORY OF OPERATION (CONTINUED)
    The circuit in Figure 9 sums a current through a 1M
    resistor
    (Rb) offsetting the phase 2 error amplifier to create an imbalance
    in the L1 and L2 currents. Although there are many ways to
    calculate component values the approach taken here is to pick Ra,
    Rb, Rin, Vout, and inductor ESR. A value for the remaining
    resistor Rf can then be calculated.
    The first decision to be made is the current sharing ratio,
    follow the previous examples to understand the basics of
    LoadSHARE. The most common reason to imbalance the
    currents in the two phases is because of limitations on the
    available power from the input rails for each phase. Use the
    available input power and total required output power to
    determine the inductor currents for each phase.
    All references are to Figure 9
    1) Calculate the voltages V1 and V2.
    ×
    =
    ×
    =
    2) Select values for Ra and Rb (Ra is typically 62K
    ; Rb
    is typically 1M
    )
    3) Calculate the offset voltage Vos at the output of the
    offset amplifier
    Vout
    ESR
    1
    L
    Current
    1
    L
    1
    V
    +
    Vout
    ESR
    2
    L
    Current
    2
    L
    2
    V
    +
    (
    )
    Rb
    Ra
    Ra
    1
    V
    2
    V
    2
    V
    Vos
    +
    ×
    =
    4) Calculate the value for Rf
    (select a value for Rin typically 5K
    )
    =
    1
    V
    Vout
    Vout
    Vos
    Rin
    Rf
    Due to the high impedances in this circuit layout can effect the
    actual current ratio by allowing some of the switching waveforms
    to couple into the current summing path. It may be necessary to
    make some adjustment in Rf after the final layout is evaluated.
    Also the equation for Rf requires very accurate numbers for the
    voltages to insure an accurate result.
    B
    I
    -P
    HASE
    , L
    OAD
    SHARE (S
    ERIES
    R
    ESISTOR
    M
    ETHOD
    )
    A fourth but less desirable way to produce the ratio current
    between the two phases is to add a resistor in series with one of
    the inductors. This will reduce the current in the inductor that has
    the resistor and increase the current in the inductor of the opposite
    phase. The example of Figure 7 can be used to determine the
    current ratio by adding the value of the series resistor to the ESR
    value of the inductor. The added resistance will lower the overall
    efficiency
    LoadSHARE ERROR SOURCES
    With the high DC feedback gain of this second loop, all phase
    timing errors, R
    DS(On)
    mismatch, and voltage differences across the
    half bridge drivers are removed from the current sharing accuracy.
    The errors in the current sharing accuracy are derived from the
    tolerance on the inductor’s ESR and the input offset voltage
    specification of the error amplifier. The equivalent circuit is
    shown next for an absolute worst case difference of phase currents
    between the two inductors.
    VOUT
    +
    -
    ESR L2
    ESR L1
    Phase 2
    Phase 1
    Offset
    Error
    5mV
    V1
    V2
    Figure 6
    – Error Amplitude
    Nominal ESR of 6m
    . ESR ±5%
    Max offset Error = 6mV
    +5% ESR L1 = 6.3 m
    -5% ESR L2 = 5.7 m
    1
    ESRL
    V
    V
    A
    12
    =
    current
    phase
    If
    OUT
    =
    mV
    75.6
    10
    6.3
    12
    V
    1
    V
    3
    =
    ×
    ×
    =
    mV
    .6
    1
    8
    mV
    6
    1
    V
    2
    V
    =
    +
    =
    A
    32
    14.
    10
    x
    5.7
    10
    x
    .6
    1
    8
    2
    L
    ESR
    V
    -
    2
    V
    current
    Phase
    3
    3
    OUT
    =
    =
    =
    Phase 2 current is 2.32A greater than Phase 1.
    Input bias current also contributes to imbalance.
    A
    P
    P
    L
    I
    C
    A
    T
    I
    O
    N
    S
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