參數(shù)資料
型號： LX1562
廠商： Microsemi Corporation
元件分類： 基準電壓源/電流源
英文描述： SECOND-GENERATION POWER FACTOR CONTROLLER
中文描述： 第二代功率因數(shù)控制器
文件頁數(shù)： 18/25頁
文件大?。?/td> 443K
代理商： LX1562
S
ECOND
-G
ENERATION
P
OWER
F
ACTOR
C
ONTROLLER
LX1562/1563
P R O D U C T D A T A B O O K 1 9 9 6 / 1 9 9 7
Copyright 1996
Rev. 1.3 12/96
18
P
R O D U C T I O N
D
A T A
S
H E E T
A P P L I C AT I O N I N F O R M AT I O N
Maximum peak input current can be calculated using:
2P
O
η
V
P
I
P
=
where:
η ≡
Converter efficiency
V
P
≡
Peak AC input voltage
assuming:
η
= 95%, P
O
= 80W, V
Pmin
= 100
√
2 = 141
2 x 80
(.95)(141)
I
P
=
= 1.2A
I
LP/min AC
= 2 * 1.2 = 2.4A
OUTPUT VOLTAGE REQUIREMENT
(continued)
0.05
(D') Off Time Duty Cycle
0.2
(
n
)
0.1
0.3
0.4
0.5
0.6
0.7
0.8
0.9
1.0
0.15
f
n
= (1 - D') D'2
D' =
2 V
AC
V
O
η
V
O
2
4 LP
O
f =
f
n
INDUCTOR PEAK CURRENT
It can be shown by referring to Figure 33 that the inductor peak
current is always twice the average input current.
Inductor Peak
Current Envelope
Average
AC Input Current
I
L
T
ON
T
OFF
FIGURE 33
— INDUCTOR CURRENT
Σ
I
IN(t)
=
AVE [ I
L
(t) ]
I
IN
=
=
I
INpeak
= I
P
=
I
LP
= Inductor peak current at peak input voltage.
I
L
2
(I
L
) (T)
2
1
T
I
LP
2
FIGURE 32
— NORMALIZED OPERATING FREQUENCY vs.
OFF-TIME DUTY CYCLE
INDUCTOR DESIGN
The inductor value is calculated assuming a 50KHz operating
frequency at the nominal AC voltage using the following equation:
L
1
=
where:
η ≡
Efficiency
V
O
≡
Output DC voltage
V
P
≡
Peak AC input voltage
T
≡
Switching period
P
O
≡
Output Power
L
1
I
LP
B
≡
Required inductance
≡
1.724 * 10
-8
m
≡
Maximum flux density
I
LP
≡
Maximum peak inductor current
P
CU
≡
Maximum copper dissipation
Assume: P
CU
= 1.6W (2% of total output)
2
P
CU
2
1.724 * 10
-8
1.6
450 * 10
-6
* (2.4)
2
0.15
η
T V
P
2
4 P
O
V
O
- V
P
V
O
L
1
=
= 448μH
choose T = 20μsec (50kHz)
Figure 32 shows that at nominal AC line (D' = 0.74) the normalized
frequency is 0.142 and dropping to 0.13 at maximum line
condition. This translates to a 10% drop in operating frequency
which is still well above the audible range.
Once the inductance is known, we can either use the area
product method (AP) or the K
(based on copper losses method),
for selecting proper core size. In this example, we apply the K
g
approach using the following steps:
Step 1:
Calculate K
g
using
K
g
=
(
)
2
where:
L
1
B
K
g
=
= 3.21 * 10
-12
m
5
.95 (
) 20 * 10
-6
* (120
√
2)
2
4 * 80
230 - 120
√
2
230
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