參數(shù)資料
型號(hào): LT1107CS8-5#TR
廠商: LINEAR TECHNOLOGY CORP
元件分類: 穩(wěn)壓器
英文描述: 1.5 A SWITCHING REGULATOR, 88 kHz SWITCHING FREQ-MAX, PDSO8
封裝: SOIC-8
文件頁(yè)數(shù): 14/16頁(yè)
文件大小: 207K
代理商: LT1107CS8-5#TR
7
LT1107
1107fa
Inductor Selection –– Step-Up Converter
In a step-up, or boost converter (Figure 1), power gener-
ated by the inductor makes up the difference between
input and output. Power required from the inductor is
determined by:
where VD is the diode drop (0.5V for a 1N5818 Schottky).
Energy required by the inductor per cycle must be equal or
greater than:
in order for the converter to regulate the output.
When the switch is closed, current in the inductor builds
according to:
where R
′ is the sum of the switch equivalent resistance
(0.8
typical at 25°C) and the inductor DC resistance.
When the drop across the switch is small compared to VIN,
the simple lossless equation:
As an example, suppose 12V at 60mA is to be generated
from a 3V to 6V input. Recalling equation (1),
Energy required from the inductor is:
Picking an inductor value of 33
H with 0.2 DCR results
in a peak switch current of:
Substituting IPEAK into Equation 4 results in:
Since 11.9
J > 9.05J, the 33H inductor will work. This
trial-and-error approach can be used to select the opti-
mum inductor.
A resistor can be added in series with the ILIM pin to invoke
switch current limit. The resistor should be picked so the
calculated IPEAK at minimum VIN is equal to the Maximum
Switch Current (from Typical Performance Characteristic
curves). Then, as VIN increases, peak switch current is
held constant, resulting in increasing efficiency.
Inductor Selection –– Step-Down Converter
The step-down case (Figure 2) differs from the step-up in
that the inductor current flows through the load during
both the charge and discharge periods of the inductor.
Current through the switch should be limited to ~650mA
in this mode. Higher current can be obtained by using an
external switch (see LT1111 and LT1110 data sheets). The
ILIM pin is the key to successful operation over varying
inputs.
After establishing output voltage, output current and input
voltage range, peak switch current can be calculated by the
formula:
U
S
A
O
PPLICATI
WU
U
I FOR ATIO
P
f
L
OSC
/( )
2
It
V
R
e
L
IN
Rt
L
()
( )
=
13
It
V
L
t
L
IN
()=
()
4
can be used. These equations assume that at t = 0,
inductor current is zero. This situation is called “discon-
tinuous mode operation” in switching regulator parlance.
Setting “t” to the switch ON time from the LT1107 speci-
fication table (typically 11
s) will yield IPEAK for a specific
“L” and VIN. Once IPEAK is known, energy in the inductor
at the end of the switch ON time can be calculated as:
EL must be greater than PL/fOSC for the converter to deliver
the required power. For best efficiency IPEAK should be
kept to 1A or less. Higher switch currents will cause
excessive drop across the switch resulting in reduced
efficiency. In general, switch current should be held to as
low a value as possible in order to keep switch, diode and
inductor losses at a minimum.
P
f
mW
kHz
J
L
OSC
==
570
63
905
7
.( )
EH
A
J
L =
()( ) =
1
2
33
085
1191
9
2
..
( )
ELI
L
PEAK
=
1
2
5
2
()
PV
V
mA
mW
L =+
()( )=
12
0 5
3
60
570
6
.( )
I
V
emA
PEAK
s
H
=
=
3
1
850
8
111
33
()
PV
V
I
L
OUT
D
IN MIN
OUT
=+
()
()
1
I
DC
VV
V
PEAK
OUT
D
IN
SW
D
=
+
2
10
()
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