參數(shù)資料
型號: LM3402MRX
廠商: NATIONAL SEMICONDUCTOR CORP
元件分類: 穩(wěn)壓器
英文描述: 0.5A Constant Current Buck Regulator for Driving High Power LEDs
中文描述: 0.94 A SWITCHING REGULATOR, PDSO8
封裝: PLASTIC, TSOP-8
文件頁數(shù): 19/24頁
文件大小: 431K
代理商: LM3402MRX
signing to a desired
Δ
v
of 25 mV and assuming that the
average inductor current will equal the desired average LED
current of 350 mA yields the target current ripple in the in-
ductor and LEDs:
Δ
i
F
= Δ
i
L
= Δ
v
SNS
/ R
SNS
, R
SNS
= V
SNS
/ I
F
Δ
i
F
= 0.025 / 0.57 = 43.8 mA
With the target ripple current determined the inductance can
be chosen:
L
MIN
= [(60 – 49.2) x 2.7 x 10
-6
] / (0.044) = 663 μH
The closest standard inductor value is 680 μH. As with the
previous example, the average current rating should be
greater than 350 mA. Separation between the LM3402HV
drivers and the LED arrays mean that heat from the inductor
will not threaten the lifetime of the LEDs, but an overheated
inductor could still cause the LM3402HV to enter thermal
shutdown.
The inductance itself of the standard part chosen is ±20%.
With this tolerance the typical, minimum, and maximum in-
ductor current ripples can be calculated:
Δ
i
F(TYP)
= [(60 - 49.2) x 2.7 x 10
-6
] / 680 x 10
-6
= 43 mA
P-P
Δ
i
F(MIN)
= [(60 - 49.2) x 2.7 x 10
-6
] / 816 x 10
-6
= 36 mA
P-P
Δ
i
F(MAX)
= [(60 - 49.2) x 2.7 x 10
-6
] / 544 x 10
-6
= 54 mA
P-P
The peak LED/inductor current is then estimated:
I
L(PEAK)
= I
L
+ [Δ
i
L(MAX)
] / 2
I
L(PEAK)
= 0.35 + 0.027 = 377 mA
In the case of a short circuit across the LED array, the
LM3402HV will continue to deliver rated current through the
short but will reduce the output voltage to equal the CS pin
voltage of 200 mV. Worst-case peak current in this condition
would be equal to:
Δ
i
F(LED-SHORT)
= [(63 – 0.2) x 2.7 x 10
-6
] / 544 x 10
-6
= 314 mA
P-P
I
F(PEAK)
= 0.35 + 0.156 = 506 mA
In the case of a short at the switch node, the output, or from
the CS pin to ground the short circuit current limit will engage
at a typical peak current of 735 mA. In order to prevent in-
ductor saturation during these fault conditions the inductor’s
peak current rating must be above 735 mA. A 680 μH off-the
shelf inductor rated to 1.2A (peak) and 0.72A (average) with
a DCR of 1.1
will be used for the green LED array.
R
SNS
A preliminary value for R
was determined in selecting
Δ
i
L
. This value should be re-evaluated based on the calcula-
tions for
Δ
i
F
:
Sub-1
resistors are available in both 1% and 5% tolerance.
A 1%, 0.56
device is the closest value, and a 0.125W, 0805
size device will handle the power dissipation of 69 mW. With
the resistance selected, the average value of LED current is
re-calculated to ensure that current is within the ±5% toler-
ance requirement. From the expression for LED current ac-
curacy:
I
F
= 0.19 / 0.56 + 0.043 / 2 = 361 mA, 3% above 350 mA
INPUT CAPACITOR
Following the calculations from the Input Capacitor section,
Δ
v
will be 1%
P-P
= 600 mV. The minimum required ca-
pacitance is:
C
IN(MIN)
= (0.35 x 2.7 x 10
-6
) / 0.6 = 1.6 μF
In expectation that more capacitance will be needed to pre-
vent power supply interaction a 2.2 μF ceramic capacitor
rated to 100V with X7R dielectric in an 1812 case size will be
used. From the Design Considerations section, input rms cur-
rent is:
I
IN-RMS
= 0.35 x Sqrt(0.82 x 0.18) = 134 mA
Ripple current ratings for 1812 size ceramic capacitors are
typically higher than 2A, more than enough for this design.
RECIRCULATING DIODE
The input voltage of 60V ±5% requires Schottky diodes with
a reverse voltage rating greater than 60V. Some manufactur-
ers provide Schottky diodes with ratings of 70, 80 or 90V;
however the next highest standard voltage rating is 100V.
Selecting a 100V rated diode provides a large safety margin
for the ringing of the switch node and also makes cross-ref-
erencing of diodes from different vendors easier.
The next parameters to be determined are the forward current
rating and case size. In this example the high duty cycle (D =
49.2 / 60 = 82%) places less thermals stress on D1 and more
on the internal power MOSFET of the LM3402. The estimated
average diode current is:
I
D
= 0.361 x 0.18 = 65 mA
A Schottky with a forward current rating of 0.5A would be ad-
equate, however at 100V the majority of diodes have a mini-
mum forward current rating of 1A. To determine the proper
case size, the dissipation and temperature rise in D1 can be
calculated as shown in the Design Considerations section.
V
D
for a small case size such as SOD-123F in a 100V, 1A
19
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LM3403J 制造商:National Semiconductor 功能描述:3403 NSC'94 S4A1D
LM3403J/A+ 制造商:未知廠家 制造商全稱:未知廠家 功能描述:Voltage-Feedback Operational Amplifier
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