參數(shù)資料
型號(hào): L584
廠商: 意法半導(dǎo)體
英文描述: MULTIFUNCTION INJECTION INTERFACE
中文描述: 多功能注射液界面
文件頁(yè)數(shù): 10/13頁(yè)
文件大?。?/td> 178K
代理商: L584
To have a very short off time when the L584 input
goes LOW, aninternal zeneris availableon pin 16.
This zener is used withan external divider, R8, R9,
as shownin figure 2. Suitable values can be found
from:
V
pin 16
15V+ V
BEQ2
+ VRsense
R9 + R8
R8
V
CQ2
V
pin 16
.
(V
CQ2
is thevoltageat thecollectorofQ2.V
CQ2
max
is 47Vif thepin8 is usedfor slow recirculationas in
fig. 2).
To ensurestability,asmall capacitor(about200pF)
must beconnectedbetweenthe baseandcollector
of Q2when pin 16 is used.
A differentopportunityfora fastoff timeis basedon
the use of the externalzener diode Dz. In this case
also themaximum Dz voltagevalueis 47V.
LOAD DUMP PROTECTION
To protectthedeviceagainstthepositiveloaddump
it is necessaryto connectpin 1 to V
S
. In thiscase,
if V
S
ishigher than32V,the deviceturns offQ
2
and
turns on Q
1
. Theexternalresistor R
6
must be used
(see application circuit) to avoidthat pin 8 voltage
exceeds50V duringload dump. R
6
mustbe :
V
DUMP
– V
8
R
6
>
I
dp
where V
DUMP
is the dump voltage value and V
8
:
4.75V < V
8
< 47V.
ForthisR
6
value,theminimum supplyvoltageV
Smin
guaranteeingQ1 operationis given by :
V
Smin
=
R6
Ip
B
Q1
(+
2
)
V
BEQ1
R
5
+
V
8sat
In relationto V
Smin
it isno moreverified I
dp
= 35 I
ref
(typ) even if the system correct operation is com-
pletely guaranteed.
The L584 application circuit suggested in these
notesallowsthe useof inductiveloadswith thelow-
estpossibleseries resistance(compatiblewith con-
structionalrequirements)andthereforereducesno-
tablythe powerdissipation.
For example, an electronic injector driven from
14.4Vwhich draws 2.4A has a series resistanceof
6
anddissipates34.56W.Usingthiscircuitainjec-
torwith a1
seriesresistancecanbe usedandthe
power dissipationis :
P
d
=R
L
I
L2
+ V
D
I
L
(1–
σ
) + V
sat
IL
σ
+ R
S
I
L2
σ
whereR
L
= resistance of injector = 1
V
D
= drop across diode, V
D
1V
V
sat
= saturationvoltage of Q2,
1V
R
S
= R11 = 185m
σ
= duty cycle = 20%
therefore:
Pd
5.76+ 1.92+ 0.48+ 0.21 = 8.37W
This given two advantages: the size (and cost) of
the injector is reduced and the drive current is re-
ducedfrom 2.4A to about0.4A.
Theapplicationcircuitoffigure9isverysimilar tofig-
ure2 exceptthat itshows the use of two supplies:
onefor the control circuit, one for the power stage.
L584
10/13
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