參數(shù)資料
型號： HA-2556
廠商： Intersil Corporation
英文描述： 57MHz, Wideband, Four Quadrant,Voltage Output Analog Multiplier(57MHz,寬頻,四象限,電壓輸出模擬乘法器)
中文描述： 57MHz，寬帶，四象限，電壓輸出模擬乘法器（57MHz，寬頻，四象限，電壓輸出模擬乘法器）
文件頁數(shù)： 5/15頁
文件大?。?/td> 245K
代理商： HA-2556
5
Typical Applications
Let’s first examine the Balance Concept as it applies to the
standard multiplier configuration (Figure 2).
HA-2556
V
X
+
A
+
-
Signals A and B are input to the multiplier and the signal W
is the result. By substituting the signal values into the
Balance equation you get:
(A) x (B) = 5(W)
And solving for W:
W =A 5
Notice that the output (W) enters the equation in the
feedback to the Z stage. The Balance Equation does not test
for stability, so remember that you must provide negative
feedback. In the multiplier configuration, the feedback path is
connected to V
Z
+ input, not V
Z
-. This is due to the inversion
that takes place at the summing node just prior to the output
amplifier. Feedback is not restricted to the Z stage, other
feedback paths are possible as in the Divider Configuration
shown in Figure 3.
Inserting the signal values A, B and W into the Balance
Equation for the divider configuration yields:
Solving for W yields:
Notice that, in the divider configuration, signal B must remain
≥
0 (positive) for the feedback to be negative. If signal B is
negative, then it will be multiplied by the V
X-
input to produce
positive feedback and the output will swing into the rail.
Signals may be applied to more than one input at a time as
in the Squaring configuration in Figure 4:
Here the Balance equation will appear as:
Which simplifies to:
The last basic configuration is the Square Root as shown in
Figure 5. Here feedback is provided to both X and Y inputs.
The Balance equation takes the form:
Which equates to:
The four basic configurations (Multiply, Divide, Square and
Square Root) as well as variations of these basic circuits
have many uses.
Frequency Doubler
For example, if ACos(
ωτ
) is substituted for signal A in the
Square function, then it becomes a Frequency Doubler and
the equation takes the form:
And using some trigonometric identities gives the result:
1/5V
X
Y
V
OUT
Z
V
X
-
V
Y
+
V
Y
-
V
Z
+
V
Z
-
∑
W
B
+
-
A
+
-
+
-
FIGURE 2. MULTIPLIER
HA-2556
1/5V
X
Y
V
OUT
Z
V
X
+
V
X
-
V
Y
+
V
Y
-
V
Z
+
V
Z
-
∑
W
A
B
+
-
+
-
+
-
A
+
-
FIGURE 3. DIVIDER
-W
(
)
B
( )
5V x -A
)
=
W =B
(A) x (A)
5(W)
=
HA-2556
1/5V
X
Y
V
OUT
Z
V
X
+
V
X
-
V
Y
+
V
Y
-
V
Z
+
V
Z
-
∑
W
A
A
+
-
+
-
+
-
+
-
FIGURE 4. SQUARE
W
2
5
------
=
HA-2556
1/5V
X
Y
V
OUT
Z
V
X
+
V
X
-
V
Y
+
V
Y
-
V
Z
+
V
Z
-
W
A
∑
+
-
+
-
A
+
-
+
-
FIGURE 5. SQUARE ROOT (FOR A > 0)
W
(
)
W
–
(
)
×
5
A
–
(
)
=
W
5A
=
ACos
ωτ
(
)
(
)
ACos
ωτ
(
)
(
)
×
5 W
)
=
W
2
------
1
Cos 2
ωτ
)
+
(
)
=
HA-2556
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