參數(shù)資料
型號: CLC5802
廠商: National Semiconductor Corporation
英文描述: Dual Low-Noise, Voltage Feedback Op Amp
中文描述: 雙低噪聲,電壓反饋運(yùn)算放大器
文件頁數(shù): 10/12頁
文件大?。?/td> 420K
代理商: CLC5802
Application Information
(Continued)
A resistive divider made from the 143
and 60.4
resistors
was chosen to reduce the loop-gain and stabilize the net-
work. The CLC5802 composite integrator provides integra-
tion over five decades of operation. R and C set the integra-
tor’s gain. Figure 4 shows the frequency and phase
response of the circuit in Figure 3 with R = 44.2
and C =
360pF.
K: R2/(R1 + R2)
A
0
: Op amp low Frequency open loop gain
Positive Peak Detector
The CLC5802’s dual amplifiers can be used to implement a
unity-gain peak detector circuit as shown in Figure 5
The acquisition speed of this circuit is limited by the dynamic
resistance of the diode when charging C
hold
. A plot of the cir-
cuit’s performance is shown in Figure 6with a 1MHz sinusoi-
dal input.
A current source, built around Q1, provides the necessary
bias current for the second amplifier and prevents saturation
when power is applied. The resistor, R, closes the loop while
diode D
2
prevents negative saturation when V
IN
is less than
V
C
. A MOS-type switch (not shown) can be used to reset the
capacitor’s voltage.
The maximum speed of detection is limited by the delay of
the op amp and the diodes. The use of Schottky diodes will
provide faster response.
Adjustable or Bandpass Equalizer
A “boost” equalizer can be made with the CLC5802 by sum-
ming a bandpass response with the input signal, as shown in
Figure 7
The overall transfer function is shown in Equation (3)
(3)
To build a boost circuit, use the design Equation 4 and 5.
(4)
(5)
Select R
and C using Equation (4) Use reasonable values
for high frequency circuits - R
between 10
and 5k
, C be-
tween 10pF and 2000pF. Use Equation (5) to determine the
parallel combination of R
and R
. Select R
and R
by ei-
ther the 10
to 5k
criteria or by other requirements based
on the impedance V
is capable of driving. Finish the design
by determining the value of K from Equation (6)
DS101341-29
FIGURE 4.
DS101341-30
FIGURE 5.
DS101341-31
FIGURE 6.
DS101341-32
FIGURE 7.
C
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