
11
http://www.national.com
where Z
o(5602)
(j
ω
) is the output impedance of the
CLC5602 and |Z
o(5602)
(j
ω
)| << R
m
.
The load voltage and current will fall in the ranges:
The CLC5602’s high output drive current and low
distortion make it a good choice for this application.
Full Duplex Cable Driver
The circuit shown in Figure 16 below, operates as a full
duplex cable driver which allows simultaneous transmis-
sion and reception of signals on one transmission line.
The circuit on either side of the transmission line uses are
CLC5602 as a cable driver, and the second CLC5602 as
a receiver. V
oA
is an attenuated version of Vi
nA
, while V
oB
is an attenuated version of V
inB
.
Figure 16: Full Duplex Cable Driver
R
m1
is used to match the transmission line. R
f2
and R
g2
set the DC gain of the CLC5602, which is used in a
difference mode. R
t2
provides good CMRR and DC
offset. The transmitting CLC5602’s are shown in a unity
gain configuration because they consume the least
power of any gain, for a given load. For proper operation
we need R
f2
= R
g2
.
The receiver output voltages are:
where A is the attenuation of the cable, Z
o(5602)
(j
ω
) is the
output impedance of the CLC5602 (see the
Closed-Loop
Output Resistance
plot), and
|
Z
o(5602)
(j
ω
)
|
<< R
m1
.
We selected the component values as follows:
I
R
f1
= 1.0k
, the recommended value for the
CLC5602 at unity gain
I
R
m1
= Z
o
= 50
, the characteristic impedance
of the transmission line
I
R
f2
= R
g2
= 750
≥
R
m1
, the recommended
value for the CLC5602 at A
v
= 2
)–R
2
I
These values give excellent isolation from the other input:
The CLC5602 provides large output current drive, while
consuming little supply current, at the nominal bias point.
It also produces low distortion with large signal swings
and heavy loads. These features make the CLC5602 an
excellent choice for driving transmission lines.
R
f1
R
f2
+
-
R
t1
Z
0
-
+
1/2
CLC5602
V
inA
R
g2
R
t2
R
m1
V
oB
R
f1
R
f2
+
-
R
t1
-
+
V
inB
R
g2
R
t2
R
m1
V
oA
1/2
CLC5602
1/2
CLC5602
1/2
CLC5602
R
(R
||R
25
t2
f2
g2
m1
=
=
V
V
38dB, f
≈
5.0MHz
oA(B)
inB(A)
=
V
V
A
V
2
1
R
R
Z
(j )
R
outA(B)
inA(B)
inB(A)
f2
g2
o(5602)
m1
≈
+
+
V
n V
I
I
n
o
o
≤
≤
max
max