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參數(shù)資料
| 型號： | AN3370K |
| 廠商： | PANASONIC CORP |
| 元件分類： | 消費家電 |
| 英文描述： | Circular Connector; No. of Contacts:37; Series:MS27656; Body Material:Aluminum; Connecting Termination:Crimp; Connector Shell Size:15; Circular Contact Gender:Socket; Circular Shell Style:Wall Mount Receptacle RoHS Compliant: No |
| 中文描述： | SPECIALTY CONSUMER CIRCUIT, PSIP10 |
| 封裝： | SHRINK, PLASTIC, SIP-10 |
| 文件頁數(shù)： | 4/4頁 |
| 文件大?。?/td> | 42K |
| 代理商： | AN3370K |
ICs for VCR
AN3370K
1
2
3
4
5
6
7
9
8
10
0.01
μ
F
V
CC
=12V
V
H
= 5V
0.01
μ
F
100
μ
F
4.7
μ
H
C
1
C
2
R
X
0.01
μ
F
L
X
C
X1
C
X2
AN3370K
Flying Erase
H
Erase Head L
I
Supplementary Explanation
Characteristic Curve
1) Internal Oscillation Frequency
An internal oscillation frequency is determined by the fol-
lowing expression. Set C
X1
, C
X2
, and L
X
according to a fre-
quency.
f
OSC
=
L
x
·C
X1
· C
X2
C
X1
+ C
X2
In order to obtain stable oscillation, set C
X1
/C
X2
near 1 and
absolute value of C
X1
, C
X2
to such a considerable extent that
an internal IC capacitance (approx. 5pF) and an external
PCB capacitance can be ignored.
2) R
X
Output current amplitude from the IC is determined by the
external resistor R
X
of the Pin7 ; it is approximately as
shown in Fig. 1. Therefore, use within the following range.
I
5
=20mA
pp
to 65mA
pp
.
3) Do not apply the Pin1 voltage when V
CC
is off.
Use the Pin2 voltage open.
4) Output Dynamic Range
Since the output pin (5) dynamic range of the AN3370K is
8V
PP
(at V
CC
=12V), set a combination of C
1
, C
2
, and erase head
inductance (L) so that the following will be ensured.
I
5
(mA
pp
)
×
load impedance < 8V
PP
.
5) Serial and Parallel Resonance Points
Serial resonance
frequency
Since Pin5 amplitude is minimized at a point of f
1
, set f
1
so that it will almost coincide with f
OSC
.
Parallel resonance frequency
Suppose the internal capacitance of the Pin5 is
C
5
, then parallel resonance frequency is
Although an erase head current is maximized at this point,
set f
2
/f
OSC
= 1.25 to 1.4
1
2
π
· · · · · · · · · · · · · · · · · (1)
f
1
=
1
L (C
1
+ C
2
)
2
π
(2)
f
2
=
L
2
π
· · · (3)
L
C
5
· C
1
C
5
+ C
1
C
2
+
Fig. 1.
..
· · · · · · · · ·
I
5
–R
X
I
5
P
)
R
X
(k
)
0
5
10
15
20
25
0
20
40
60
80
100
V
CC
=12V
L
X
= 5.6
μ
H
C
= C
= 68pF
fosc=10.8MHz
I
50
R
X
0.047
μ
F
5
5
7
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