+VS +IN 鈥揑N 0.1F 10F 0.1F REF V
鍙冩暩(sh霉)璩囨枡
鍨嬭櫉(h脿o)锛� AD8429BRZ
寤犲晢锛� Analog Devices Inc
鏂囦欢闋佹暩(sh霉)锛� 10/20闋�
鏂囦欢澶�?銆�?/td> 0K
鎻忚堪锛� IC OP AMP INST LOW NOISE 8SOIC
妯�(bi膩o)婧�(zh菙n)鍖呰锛� 1
鏀惧ぇ鍣ㄩ鍨嬶細 鍎€琛�
闆昏矾鏁�(sh霉)锛� 1
杞�(zhu菐n)鎻涢€熺巼锛� 22 V/µs
-3db甯跺锛� 15MHz
闆绘祦 - 杓稿叆鍋忓锛� 150nA
闆诲 - 杓稿叆鍋忕Щ锛� 50µV
闆绘祦 - 闆绘簮锛� 6.7mA
闆绘祦 - 杓稿嚭 / 閫氶亾锛� 35mA
闆诲 - 闆绘簮锛屽柈璺�/闆欒矾(±)锛� ±4 V ~ 18 V
宸ヤ綔婧害锛� -40°C ~ 125°C
瀹夎椤炲瀷锛� 琛ㄩ潰璨艰
灏佽/澶栨锛� 8-SOIC锛�0.154"锛�3.90mm 瀵級
渚涙噳(y墨ng)鍟嗚ō(sh猫)鍌欏皝瑁濓細 8-SO
鍖呰锛� 绠′欢
AD8429
Rev. 0 | Page 18 of 20
R
AD8429
+VS
+IN
鈥揑N
0.1F
10F
0.1F
REF
VOUT
鈥揤S
RG
CD
10nF
CC
1nF
CC
1nF
4.02k
09
73
0-
0
63
Figure 53. RFI Suppression
The filter limits the input signal bandwidth, according to the
following relationship:
)
2
(
2
1
C
D
DIFF
C
R
uency
FilterFreq
+
=
C
CM
RC
uency
FilterFreq
2
1
=
where CD 鈮� 10 CC.
CD affects the difference signal, and CC affects the common-mode
signal. Choose values of R and CC that minimize RFI. A mismatch
between R 脳 CC at the positive input and R 脳 CC at the negative
input degrades the CMRR of the AD8429. By using a value of
CD that is one magnitude larger than CC, the effect of the
mismatch is reduced, and performance is improved.
Resistors add noise; therefore, the choice of resistor and capacitor
values depends on the desired tradeoff between noise, input
impedance at high frequencies, and RFI immunity. The resistors
used for the RFI filter can be the same as those used for input
protection.
CALCULATING THE NOISE OF THE INPUT STAGE
R2
RG
R1
SENSOR
AD8429
09
73
0-
0
64
Figure 54. Source Resistance from Sensor and Protection Resistors
The total noise of the amplifier front end depends on much
more than the 1 nV/鈭欻z specification of this data sheet. There
are three main contributors: the source resistance, the voltage
noise of the instrumentation amplifier, and the current noise of
the instrumentation amplifier.
In the following calculations, noise is referred to the input
(RTI). In other words, everything is calculated as if it appeared
at the amplifier input. To calculate the noise referred to the
amplifier output (RTO), simply multiply the RTI noise by the
gain of the instrumentation amplifier.
Source Resistance Noise
Any sensor connected to the AD8429 has some output resistance.
There may also be resistance placed in series with inputs for pro-
tection from either overvoltage or radio frequency interference.
This combined resistance is labeled R1 and R2 in Figure 54. Any
resistor, no matter how well made, has an intrinsic level of noise.
This noise is proportional to the square root of the resistor value.
At room temperature, the value is approximately equal to
4 nV/鈭欻z 脳 鈭�(resistor value in k惟).
For example, assuming that the combined sensor and protec-
tion resistance on the positive input is 4 k惟, and on the negative
input is 1 k惟, the total noise from the input resistance is
(
) (
)
=
+
=
+
16
64
1
4
2
8.9 nV/鈭欻z
Voltage Noise of the Instrumentation Amplifier
The voltage noise of the instrumentation amplifier is calculated
using three parameters: the device input noise, output noise,
and the RG resistor noise. It is calculated as follows:
Total Voltage Noise =
(
) (
)(
)2
2
/
Resistor
R
of
Noise
Input
G
Noise
Output
G
+
For example, for a gain of 100, the gain resistor is 60.4 惟. There-
fore, the voltage noise of the in-amp is
()
(
)2
2
0604
.
0
4
1
100
/
45
+
= 1.5 nV/鈭欻z
Current Noise of the Instrumentation Amplifier
Current noise is calculated by multiplying the source resistance
by the current noise.
For example, if the R1 source resistance in Figure 54 is 4 k惟,
and the R2 source resistance is 1 k惟, the total effect from the
current noise is calculated as follows:
()
(
)
(
)2
2
5
.
1
5
.
1
4
+
= 6.2 nV/鈭欻z
Total Noise Density Calculation
To determine the total noise of the in-amp, referred to input,
combine the source resistance noise, voltage noise, and current
noise contribution by the sum of squares method.
For example, if the R1 source resistance in Figure 54 is 4 k惟, the
R2 source resistance is 1 k惟, and the gain of the in-amps is 100,
the total noise, referred to input, is
2
.
6
5
.
1
9
.
8
+
= 11.0 nV/鈭欻z
鐩搁棞(gu膩n)PDF璩囨枡
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