參數資料
型號: AD8200
廠商: Analog Devices, Inc.
元件分類: 運動控制電子
英文描述: High Common-Mode Voltage, Single Supply Difference Amplifier
中文描述: 高共模電壓,單電源差分放大器
文件頁數: 7/8頁
文件大?。?/td> 186K
代理商: AD8200
REV. 0
AD8200
–7–
Internal Signal Overload Considerations
When configuring gain for values other than 20, the maximum
input voltage with respect to the supply voltage and ground
must be considered, since either the preamplifier or the output
buffer will reach its full-scale output (approximately
V
S
– 0.2
V
)
with large differential input voltages. The input of the AD8200
is limited to (
V
S
– 0.2)
÷
10, for overall gains
10, since the
preamplifier, with its fixed gain of
×
10, reaches its full-scale
output before the output buffer. For gains greater than 10, the
swing at the buffer output reaches its full-scale first and limits
the AD8200 input to (
V
S
– 0.2)
÷
G
, where
G
is the overall gain.
LOW-PASS FILTERING
In many transducer applications it is necessary to filter the sig-
nal to remove spurious high-frequency components, including
noise, or to extract the mean value of a fluctuating signal with a
peak-to-average ratio (PAR) greater than unity. For example, a
full-wave rectified sinusoid has a PAR of 1.57, a raised cosine
has a PAR of 2, and a half-wave sinusoid has a PAR of 3.14.
Signals having large spikes may have PARs of 10 or more.
When implementing a filter, the PAR should be considered so
the output of the AD8200 preamplifier (A1) does not clip before
A2, since this nonlinearity would be averaged and appear as an
error at the output. To avoid this error, both amplifiers should
be made to clip at the same time. This condition is achieved
when the PAR, is no greater than the gain of the second ampli-
fier (2 for the default configuration). For example, if a PAR of 5
is expected, the gain of A2 should be increased to 5.
Low-pass filters can be implemented in several ways using the
features provided by the AD8200. In the simplest case, a single-
pole filter (20 dB/decade) is formed when the output of A1 is
connected to the input of A2 via the internal 100 k
resistor by
strapping Pins 3 and 4, and a capacitor added from this node to
ground, as shown in Figure 8. If a resistor is added across the
capacitor to lower the gain, the corner frequency will increase; it
should be calculated using the parallel sum of the resistor and
100 k
.
IN GND A1
A2
+IN
NC +V
S
OUT
AD8200
5V
C
V
CM
OUT
F
C
=
1
2 C10
5
C IN FARADS
V
DIFF
2
V
DIFF
2
NC = NO CONNECT
Figure 8. A Single-Pole, Low-Pass Filter Using the Internal
100 k
Resistor
If the gain is raised using a resistor, as shown in Figure 8, the
corner frequency is lowered by the same factor as the gain is
raised. Thus, using a resistor of 200 k
(for which the gain
would be doubled) the corner frequency is now 0.796 Hz-
μ
F,
(0.039
μ
F for a 20 Hz corner frequency.)
IN GND A1
A2
+IN
NC +V
S
OUT
AD8200
OUT
V
CM
C
255k
C
F
C
= 1Hz
F
5V
NC = NO CONNECT
V
DIFF
2
V
DIFF
2
Figure 9. 2-Pole Low-Pass Filter
A 2-pole filter (with a roll-off of 40 dB/decade) can be imple-
mented using the connections shown in Figure 9. This is a
Sallen-Key form based on a
×
2 amplifier. It is useful to remem-
ber that a 2-pole filter with a corner frequency f
2
and a 1-pole
filter with a corner at f
1
have the same attenuation at the
frequency (f
22
/f
1
). The attenuation at that frequency is 40 Log
(f
2
/f
1
). This is illustrated in Figure 10. Using the standard resis-
tor value shown, and equal capacitors (Figure 9), the corner
frequency is conveniently scaled at 1 Hz-
μ
F (0.05
μ
F for a 20 Hz
corner). A maximally flat response occurs when the resistor is
lowered to 196 k
and the scaling is then 1.145 Hz-
μ
F. The
output offset is raised by about 5 mV (equivalent to 250 V at
the input pins).
40LOG (f
2
/f
1
)
f
1
A
f
2
f
22
/f
1
FREQUENCY
A 1-POLE FILTER, CORNER f
1
, AND
A 2-POLE FILTER, CORNER f
, HAVE
THE SAME ATTENUATION
40LOG (f
2
/f
1
)
AT FREQUENCY f
22
/f
1
20dB/DECADE
40dB/DECADE
Figure 10. Comparative Responses of 1- and 2-Pole Low-
Pass Filters
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