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參數(shù)資料
| 型號： | AAT3220IQY-35-T1 |
| 廠商： | Advanced Analogic Technologies, Inc. |
| 英文描述： | 150mA NanoPower⑩ LDO Linear Regulator |
| 中文描述： | 150mA的NanoPower⑩LDO線性穩(wěn)壓器 |
| 文件頁數(shù)： | 12/16頁 |
| 文件大?。?/td> | 460K |
| 代理商： | AAT3220IQY-35-T1 |
AAT3220
150mA NanoPower LDO Linear Regulator
12
3220.2001.0
9.1.0
High Peak Output Current Applications
Some applications require the LDO regulator to
operate at continuous nominal levels with short
duration high current peaks. The duty cycles for
both output current levels must be taken into
account. To do so, one would first need to calcu-
late the power dissipation at the nominal continu-
ous level, then factor in the addition power dissi-
pation due to the short duration high current peaks.
For example, a 3.0V system using a AAT3220IGV-
2.5-T1 operates at a continuous 100mA load cur-
rent level and has short 150mA current peaks. The
current peak occurs for 378μs out of a 4.61ms peri-
od. It will be assumed the input voltage is 5.0V.
First the current duty cycle percentage must be
calculated:
% Peak Duty Cycle: X/100 = 378μs/4.61ms
% Peak Duty Cycle = 8.2%
The LDO Regulator will be under the 100mAload for
91.8% of the 4.61ms period and have 150mA peaks
occurring for 8.2% of the time. Next, the continuous
nominal power dissipation for the 100mAload should
be determined then multiplied by the duty cycle to
conclude the actual power dissipation over time.
P
D(MAX)
= (V
IN
- V
OUT
)I
OUT
+ (V
IN
x I
GND
)
P
D(100mA)
= (4.2V - 3.0V)100mA + (4.2V x 1.1μA)
P
D(100mA)
= 120mW
P
D(91.8%D/C)
= %DC x P
D(100mA)
P
D(91.8%D/C)
= 0.918 x 120mW
P
D(91.8%D/C)
= 110.2mW
The power dissipation for 100mA load occurring for
91.8% of the duty cycle will be 110.2mW. Now the
power dissipation for the remaining 8.2% of the
duty cycle at the 150mA load can be calculated:
P
D(MAX)
= (V
IN
- V
OUT
)I
OUT
+ (V
IN
x I
GND
)
P
D(150mA)
= (4.2V - 3.0V)150mA + (4.2V x 1.1μA)
P
D(150mA)
= 180mW
P
D(8.2%D/C)
= %DC x P
D(150mA)
P
D(8.2%D/C)
= 0.082 x 180mW
P
D(8.2%D/C)
= 14.8mW
The power dissipation for a 150mA load occurring
for 8.2% of the duty cycle will be 14.8mW. Finally,
the two power dissipation levels can be summed to
determine the total power dissipation under the
varied load.
Device Duty Cycle vs. V
DROP
V
OUT
= 2.5V @ 85 degrees C
0
0.5
1
1.5
2
2.5
3
3.5
0
10
20
30
40
50
60
70
80
90
100
Duty Cycle (%)
V
200mA
100mA
150mA
Device Duty Cycle vs. V
DROP
V
OUT
= 2.5V @ 50 degrees C
0
0.5
1
1.5
2
2.5
3
3.5
0
10
20
30
40
50
60
70
80
90
100
Duty Cycle (%)
V
200mA
150mA
Device Duty Cycle vs. V
DROP
V
OUT
= 2.5V @ 25 degrees C
0
0.5
1
1.5
2
2.5
3
3.5
0
10
20
30
40
50
60
70
80
90
100
Duty Cycle (%)
V
200mA
150mA
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相關(guān)代理商/技術(shù)參數(shù) |
參數(shù)描述 |
|---|---|
| AAT3221 | 制造商:ANALOGICTECH 制造商全稱:Advanced Analogic Technologies 功能描述:150mA NanoPower⑩ LDO Linear Regulator |
| AAT3221_08 | 制造商:ANALOGICTECH 制造商全稱:Advanced Analogic Technologies 功能描述:150mA NanoPower⑩ LDO Linear Regulator |
| AAT32212 | 制造商:ANALOGICTECH 制造商全稱:Advanced Analogic Technologies 功能描述:150mA NanoPower⑩ LDO Linear Regulator |
| AAT3221IGV-1.6-T1 | 制造商:ANALOGICTECH 制造商全稱:Advanced Analogic Technologies 功能描述:150mA NanoPower⑩ LDO Linear Regulator |
| AAT3221IGV-1.7-T1 | 制造商:ANALOGICTECH 制造商全稱:Advanced Analogic Technologies 功能描述:150mA NanoPower⑩ LDO Linear Regulator |
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