參數(shù)資料
型號: AAT3201IGV-2.3-T1
廠商: Advanced Analogic Technologies, Inc.
英文描述: 150mA OmniPower LDO Linear Regulator
中文描述: 150mA的OmniPower LDO線性穩(wěn)壓器
文件頁數(shù): 12/14頁
文件大?。?/td> 220K
代理商: AAT3201IGV-2.3-T1
AAT3201
150mA OmniPower LDO Linear Regulator
12
3201.2002.3.0.91
High Peak Output Current Applications
Some applications require the LDO regulator to
operate at continuous nominal levels with short
duration high current peaks. The duty cycles for
both output current levels must be taken into
account. To do so, one would first need to calcu-
late the power dissipation at the nominal continu-
ous level, then factor in the addition power dissipa-
tion due to the short duration high current peaks.
For example, a 2.5V system using a AAT3221/
2IGV-2.5-T1 operates at a continuous 100mA load
current level and has short 150mA current peaks.
The current peak occurs for 378μs out of a 4.61ms
period. It will be assumed the input voltage is 5.0V.
First, the current duty cycle percentage must be
calculated:
% Peak Duty Cycle: X/100 = 378ms/4.61ms
% Peak Duty Cycle = 8.2%
The LDO Regulator will be under the 100mA load
for 91.8% of the 4.61ms period and have 150mA
peaks occurring for 8.2% of the time. Next, the
continuous nominal power dissipation for the
100mA load should be determined then multiplied
by the duty cycle to conclude the actual power dis-
sipation over time.
P
D(MAX)
= (V
IN
- V
OUT
)I
OUT
+ (V
IN
x I
GND
)
P
D(100mA)
= (5.0V - 2.5V)100mA + (5.0V x 20μA)
P
D(100mA)
= 250mW
P
D(91.8%D/C)
= %DC x P
D(100mA)
P
D(91.8%D/C)
= 0.918 x 250mW
P
D(91.8%D/C)
= 229.5mW
Device Duty Cycle vs. V
DROP
V
OUT
= 2.5V @ 85 degrees C
0
0.5
1
1.5
2
2.5
3
3.5
0
10
20
30
40
50
60
70
80
90
100
Duty Cycle (%)
V
200mA
150mA
100mA
Device Duty Cycle vs. V
DROP
V
OUT
= 2.5V @ 50 degrees C
0
0.5
1
1.5
2
2.5
3
3.5
0
10
20
30
40
50
60
70
80
90
100
Duty Cycle (%)
V
200mA
150mA
Device Duty Cycle vs. V
DROP
V
OUT
= 2.5V @ 25 degrees C
0
0.5
1
1.5
2
2.5
3
3.5
0
10
20
30
40
50
60
70
80
90
100
Duty Cycle (%)
V
200mA
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